Here's a simple recipe for making net ionic equations of your own:
\nExamine the starting equation to determine which ionic compounds are dissolved, as indicated by the (aq) symbol following the compound name.
\n\nRewrite the equation, explicitly separating dissolved ionic compounds into their component ions.
\n\nNote that polyatomic ions don't break apart in solution, so be sure to familiarize yourself with the common ones.
\nCompare the reactant and product sides of the rewritten reaction and cross out the spectator ions.
\nAny dissolved ions that appear in the same form on both sides are spectator ions. She has taught science courses at the high school, college, and graduate levels. Spectator ions serve the purpose of balancing the charges of a reaction without affecting the equilibrium of the equation in any way.
Peter J. Mikulecky, PhD, teaches science and math at Fusion Learning Center and Fusion Academy, and is a technical writer.
","authors":[{"authorId":35209,"name":"Christopher R. Hren","slug":"christopher-r-hren","description":"Christopher R. Hren has taught high school chemistry, honors chemistry, and AP Chemistry for more than 15 years. Doing so leads to a needlessly complicated reaction equation, so chemists often prefer to write net ionic equations, which omit the spectator ions. Our first product is magnesium In this case, the hydroxide OH^-1 and hydride H^+ ions from the LiOH and HBr respectively remain in solution. copper. 9.7C Identify the ions in unknown salts, using results of the tests above, 9.6C Identify the ions in unknown salts, using the tests for the specified cations and anions in 9.2C, 9.3C, 9.4C, 9.5C, 5 Identification of an unknown compound using cation tests, anion tests and flame tests. The ionic equation that includes only the particles that participate in the reaction is called. 1 comment ( 8 votes) Upvote Downvote Flag more astunix a year ago ","hasArticle":false,"_links":{"self":"https://dummies-api.dummies.com/v2/authors/9161"}}],"_links":{"self":"https://dummies-api.dummies.com/v2/books/295574"}},"collections":[],"articleAds":{"footerAd":"
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